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Tuan simplified the following expression: (b7)(b-3)/b2 (The 7,-3, and 2 are exponents.) His final answer was in the form bn. If he simplified the expression correctly, what is the value of n, the exponent on b?
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so he has \[(b^7)(b ^{-3})/b^2\] remember when multiplying exponents here....we actually add them so b^7 + b^-3 what is 7 + -3? that is the exponent on b in the numerator so we have b^4 ---- b^2 now when dividing exponents....we subtract them so b^4 / b^2 what is 4-2? that is our final exponent on b b^2 i believe...anyone correct me if i'm mistaken
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