Question

solve by extracting roots: 3x^2-x-5=0 can anypne help me with this?

Answer 1

This doesn't factorize so you have to use the quadratic formula
\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

Answer 2

plug in values from your equation
\[ax^2+bx+c\]

Answer 3

so can you help me do this?

Answer 4

im not sure where to begin

Answer 5

As Eskijoe suggested, compare your equation to the one he wrote below the formula, and compare the two. Your a is the coefficient of the squared term, your b is the coefficient of the x term, and your c is the constant.

Answer 6

right so you need to get the values of your equation that correspond to a,b and c. Then put them into the formula above to get 2 different values for x (notice the plus or minus sign).