Question

okay I am on newton raphson method
x^4 -3x^3-2x^2-12x-8=0
x0=1

Answer 1

@electrokid

Answer 2

@electrokid are you free friend> ? :)

Answer 3

\[
x_{x+1}=x_n-\frac{f(x_n)}{f'(x_n)}
\]

Answer 4

so
in x1 = I wil put all values of x0
what do I put in f'(x0)

Answer 5

is it differentiated form?

Answer 6

fist get f'(x)
put n=0.. find f(x0), f'(x0) and then x1

keep doing till you get the accuray

Answer 7

yay ^^
got it
thanks again.
sorry m bugging u all the time :D