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x+1/3=2 can someone show me how this is done?
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is it \(\frac{x+1}{3}=2\) ??
or \[x+\frac{1}{3}=2\]?
the first one
multiply both sides by 3, then subtract 1 from both sides
both sides?
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yes, whatever you do to one side, you have to do to the other
\[\frac{x+1}{3}=2\] \[\frac{x+1}{3}\times 3=2\times 3\] \[x+1=6\]
ohh
i get it! thank you so much now i'll know how to do the rest of the problems!
wait 56 isnt the answer right?
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if \(x+1=6\) then \(x=5\)
6*
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