Mathematics
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OpenStudy (anonymous):
Let u = <-4, -3>. Find the unit vector in the direction of u, and write your answer in component form.
Can someone help please!
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OpenStudy (anonymous):
unit vec = vec divided by its magnitude
1. find its magnitude
2. divide each component by that number to give you a unit vector
OpenStudy (anonymous):
@electrokid would the magnitude be 1?
OpenStudy (anonymous):
no
sqrt(ax^2+ay^2)
jimthompson5910 (jim_thompson5910):
Here's a blank xy axis
|dw:1363580299474:dw|
OpenStudy (anonymous):
ax= -4, ay= -3
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jimthompson5910 (jim_thompson5910):
now add on the vector <-4, -3>
|dw:1363580341426:dw|
jimthompson5910 (jim_thompson5910):
so you basically have this triangle
|dw:1363580394636:dw|
and you want to solve for x
OpenStudy (anonymous):
@jim_thompson5910 so would you put it over 7?
-4/7,-3/7?
jimthompson5910 (jim_thompson5910):
no you don't add 4 and 3 to get 7
jimthompson5910 (jim_thompson5910):
so x is not 7
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jimthompson5910 (jim_thompson5910):
you solve for x using the pythagorean theorem
jimthompson5910 (jim_thompson5910):
a^2 + b^2 = c^2
3^2 + 4^2 = x^2
...
...
x = ??
OpenStudy (anonymous):
@jim_thompson5910 over 25!
jimthompson5910 (jim_thompson5910):
closer, but no
jimthompson5910 (jim_thompson5910):
x is not 25 but it is....
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jimthompson5910 (jim_thompson5910):
what is x?
OpenStudy (anonymous):
@jim_thompson5910 if its x^2 then wouldnt it be 625?
jimthompson5910 (jim_thompson5910):
x^2 = 25
so
x = 5
jimthompson5910 (jim_thompson5910):
so we can say
|dw:1363581020417:dw|
jimthompson5910 (jim_thompson5910):
and the magnitude of the vector is 5 units
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OpenStudy (anonymous):
@jim_thompson5910 ohhh, I had it wrong :\ its a 3,4,5 triangle
jimthompson5910 (jim_thompson5910):
so the unit vector in component form is
\[\Large -\frac{4}{5}i - \frac{3}{5}j\]
OpenStudy (anonymous):
@jim_thompson5910 thank you!!!
jimthompson5910 (jim_thompson5910):
yw