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Mathematics 18 Online
OpenStudy (anonymous):

Let u = <-4, -3>. Find the unit vector in the direction of u, and write your answer in component form. Can someone help please!

OpenStudy (anonymous):

unit vec = vec divided by its magnitude 1. find its magnitude 2. divide each component by that number to give you a unit vector

OpenStudy (anonymous):

@electrokid would the magnitude be 1?

OpenStudy (anonymous):

no sqrt(ax^2+ay^2)

jimthompson5910 (jim_thompson5910):

Here's a blank xy axis |dw:1363580299474:dw|

OpenStudy (anonymous):

ax= -4, ay= -3

jimthompson5910 (jim_thompson5910):

now add on the vector <-4, -3> |dw:1363580341426:dw|

jimthompson5910 (jim_thompson5910):

so you basically have this triangle |dw:1363580394636:dw| and you want to solve for x

OpenStudy (anonymous):

@jim_thompson5910 so would you put it over 7? -4/7,-3/7?

jimthompson5910 (jim_thompson5910):

no you don't add 4 and 3 to get 7

jimthompson5910 (jim_thompson5910):

so x is not 7

jimthompson5910 (jim_thompson5910):

you solve for x using the pythagorean theorem

jimthompson5910 (jim_thompson5910):

a^2 + b^2 = c^2 3^2 + 4^2 = x^2 ... ... x = ??

OpenStudy (anonymous):

@jim_thompson5910 over 25!

jimthompson5910 (jim_thompson5910):

closer, but no

jimthompson5910 (jim_thompson5910):

x is not 25 but it is....

jimthompson5910 (jim_thompson5910):

what is x?

OpenStudy (anonymous):

@jim_thompson5910 if its x^2 then wouldnt it be 625?

jimthompson5910 (jim_thompson5910):

x^2 = 25 so x = 5

jimthompson5910 (jim_thompson5910):

so we can say |dw:1363581020417:dw|

jimthompson5910 (jim_thompson5910):

and the magnitude of the vector is 5 units

OpenStudy (anonymous):

@jim_thompson5910 ohhh, I had it wrong :\ its a 3,4,5 triangle

jimthompson5910 (jim_thompson5910):

so the unit vector in component form is \[\Large -\frac{4}{5}i - \frac{3}{5}j\]

OpenStudy (anonymous):

@jim_thompson5910 thank you!!!

jimthompson5910 (jim_thompson5910):

yw

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