Mathematics
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OpenStudy (anonymous):
6x^2+5-4=
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Directrix (directrix):
What are the instructions for the posted problem?
OpenStudy (anonymous):
its factoring diamond
Directrix (directrix):
There's an x missing here, I think --> 6x^2+5-4= --> after the "5."
I don't know the diamond technique. I can factor by grouping.
OpenStudy (anonymous):
yeah factor by grouping :)
Directrix (directrix):
6x^2 +5x -4
What are two numbers that multiply to -24 AND add to 5 ?
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OpenStudy (anonymous):
2?
OpenStudy (anonymous):
i think e. e
OpenStudy (anonymous):
ithink anyways i have the other side of it.. its (2x-1)( )
Directrix (directrix):
Okay. What number times -1 will multiply to -4.
-1*? = - 4 ? Help me out a little bit, and I can help you finish this. Okay?
OpenStudy (anonymous):
1
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Directrix (directrix):
-1 * 1 = -1 so that is not it.
OpenStudy (anonymous):
1 can multiply -4
OpenStudy (anonymous):
no wait wat?? i need to find a number that can multiply by 4?
Directrix (directrix):
Yes, so -1 times 4 = -4 which means
6x^2 +5x -4 = (2x-1)( ? +4 )
We're almost there. (2x) times what equals 6 x^2 ?
OpenStudy (anonymous):
3x?
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OpenStudy (anonymous):
so its 3x-4?
Directrix (directrix):
Let's see if it works:
6x^2 +5x -4 = (2x-1)( 3x +4 ) ?? @chubbytots What do you think?
OpenStudy (anonymous):
yep its right actually im answering a puzzle e. e
OpenStudy (anonymous):
that's right @Directrix
OpenStudy (anonymous):
\[3x^2-11x-20=\]
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Directrix (directrix):
>>so its 3x-4?
I did not get that.
OpenStudy (anonymous):
its 3x+4
OpenStudy (anonymous):
for da first group and the second group is?
Directrix (directrix):
(2x-1)*(3x-4) multiplies to 6x^2 -11x + 4 which is not the given problem.
Directrix (directrix):
Okay, let's try that.
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OpenStudy (anonymous):
6x^2 -11x + 4=(2x-1)(3x+4)
Directrix (directrix):
(2x-1)*(3x+4) = 6x^2 -3x + 8x -4 = 6x^2 + 5x - 4.
OpenStudy (anonymous):
thats da second question and da second question is \[3x^2-11x-20=(3x+4)( ? )\]
OpenStudy (anonymous):
i mean third**
Directrix (directrix):
I only saw the first problem.
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OpenStudy (anonymous):
i need the third problem cuz this is a pzzle v. v
Directrix (directrix):
3x^2 -11x - 20 = (3x+4) * ( )
What times 3x is equal to 3 x^2 ?
OpenStudy (anonymous):
4x+3?
Directrix (directrix):
3x^2 -11x - 20 = (3x+4) * (x )
Directrix (directrix):
3x times 4x = 12 x^2 -->doesn't work
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OpenStudy (anonymous):
is it positve 3?
Directrix (directrix):
3x times 3 = 9x.
OpenStudy (anonymous):
yes
Directrix (directrix):
Oh, you mean ( x + 3) as the second factor?
OpenStudy (anonymous):
yes
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Directrix (directrix):
(3x+4) * (x + 3 ) = 3x^2 -11x - 20 ??
3x^2 + 9x + 4x + 12 Nope.
Directrix (directrix):
We could guess forever.
OpenStudy (anonymous):
xDD i think lol and another one :O
Directrix (directrix):
Here is where we are: 3x^2 -11x - 20 = (3x+4) * (x )
We have to get -20 for the last term.
4 times what equals - 20 ?--->
OpenStudy (anonymous):
i think its x-3?
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Directrix (directrix):
4 times - 3 is not -20.
OpenStudy (anonymous):
i mean 2?
OpenStudy (anonymous):
i mean 5 sorry :o
Directrix (directrix):
4 times 5 is close but 4 times 5 does not equal -20
OpenStudy (anonymous):
hmmmm
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OpenStudy (anonymous):
i think we need to make one of them a negative right?
Directrix (directrix):
Yes.
OpenStudy (anonymous):
so-5?
Directrix (directrix):
Yes
OpenStudy (anonymous):
its x-5?
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Directrix (directrix):
3x^2 -11x - 20 = (3x+4) * (x - 5 )
Directrix (directrix):
That works.
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[6x^2+11x-10=(2x+5)(?)\]
Directrix (directrix):
It's your turn to do this one. :) You come up with the factors, and I will check.
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OpenStudy (anonymous):
i'll be guessing dou
Directrix (directrix):
That's what I ended up doing because you didn't like factoring by grouping.
OpenStudy (anonymous):
2x+1
OpenStudy (anonymous):
lol actually this s factoring by grouping.. and i need to do factor diamond
OpenStudy (anonymous):
its like two steps first is factoring by grouping and factoring diamond
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Directrix (directrix):
That diamond thing is sophisticated guessing for me.
OpenStudy (anonymous):
x. x so can we do factoring by grouping?
Directrix (directrix):
(2x+1)*(2x+5) = 4x^2 + 12x + 5 --> This is from your guess.
Directrix (directrix):
It didn't work.
OpenStudy (anonymous):
2x-5?
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Directrix (directrix):
I'm going to group.
OpenStudy (anonymous):
is it 6x10?
OpenStudy (anonymous):
6x10=60 ryt and wet going to make one of them a negative?
Directrix (directrix):
6 + 10 is not 11
Directrix (directrix):
15 and -4.
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Directrix (directrix):
x^2 + 11x - 10 = x^2 + 15x - 4x - 10
OpenStudy (anonymous):
5x+2?
Directrix (directrix):
This thread is so long that I have lost the problem.
Directrix (directrix):
(2x + 5) * ( 3x + 2)
That is my last factoring problem on this puzzle.
OpenStudy (anonymous):
so its 3x+2?
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OpenStudy (anonymous):
3x-2?
Directrix (directrix):
6x^2 + 15x - 4x - 10 = 3x(2x + 5) - 2(2x + 5) = (2x + 5) * ( 3x - 2).
Right.
OpenStudy (anonymous):
owoo that was brain storm >,<
Directrix (directrix):
The more of this stuff you do, the better you get. Except, I seem to be getting worse.
OpenStudy (anonymous):
ohh yah sure cuz when im learning this i was lazy thats why i came up here >.<
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Directrix (directrix):
What is the next factoring problem?
OpenStudy (anonymous):
how abut this?
\[7x^2+13x-2=(x+2)(?)\]
OpenStudy (anonymous):
xDD under the typing box thou
v
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v
v
v
OpenStudy (anonymous):
actually this factoring group so on this is the new lesson on our school e. e''''
OpenStudy (anonymous):
and imto lazy about it
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OpenStudy (anonymous):
xDD uhh nope o. o
OpenStudy (anonymous):
ohh well i better rap dis up cuz im gonna go early tommorow well thanks fo the help :)
Directrix (directrix):
Okay. See later on here.
OpenStudy (anonymous):
ok byee