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Mathematics 13 Online
OpenStudy (anonymous):

6x^2+5-4=

Directrix (directrix):

What are the instructions for the posted problem?

OpenStudy (anonymous):

its factoring diamond

Directrix (directrix):

There's an x missing here, I think --> 6x^2+5-4= --> after the "5." I don't know the diamond technique. I can factor by grouping.

OpenStudy (anonymous):

yeah factor by grouping :)

Directrix (directrix):

6x^2 +5x -4 What are two numbers that multiply to -24 AND add to 5 ?

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

i think e. e

OpenStudy (anonymous):

ithink anyways i have the other side of it.. its (2x-1)( )

Directrix (directrix):

Okay. What number times -1 will multiply to -4. -1*? = - 4 ? Help me out a little bit, and I can help you finish this. Okay?

OpenStudy (anonymous):

1

Directrix (directrix):

-1 * 1 = -1 so that is not it.

OpenStudy (anonymous):

1 can multiply -4

OpenStudy (anonymous):

no wait wat?? i need to find a number that can multiply by 4?

Directrix (directrix):

Yes, so -1 times 4 = -4 which means 6x^2 +5x -4 = (2x-1)( ? +4 ) We're almost there. (2x) times what equals 6 x^2 ?

OpenStudy (anonymous):

3x?

OpenStudy (anonymous):

so its 3x-4?

Directrix (directrix):

Let's see if it works: 6x^2 +5x -4 = (2x-1)( 3x +4 ) ?? @chubbytots What do you think?

OpenStudy (anonymous):

yep its right actually im answering a puzzle e. e

OpenStudy (anonymous):

that's right @Directrix

OpenStudy (anonymous):

\[3x^2-11x-20=\]

Directrix (directrix):

>>so its 3x-4? I did not get that.

OpenStudy (anonymous):

its 3x+4

OpenStudy (anonymous):

for da first group and the second group is?

Directrix (directrix):

(2x-1)*(3x-4) multiplies to 6x^2 -11x + 4 which is not the given problem.

Directrix (directrix):

Okay, let's try that.

OpenStudy (anonymous):

6x^2 -11x + 4=(2x-1)(3x+4)

Directrix (directrix):

(2x-1)*(3x+4) = 6x^2 -3x + 8x -4 = 6x^2 + 5x - 4.

OpenStudy (anonymous):

thats da second question and da second question is \[3x^2-11x-20=(3x+4)( ? )\]

OpenStudy (anonymous):

i mean third**

Directrix (directrix):

I only saw the first problem.

OpenStudy (anonymous):

i need the third problem cuz this is a pzzle v. v

Directrix (directrix):

3x^2 -11x - 20 = (3x+4) * ( ) What times 3x is equal to 3 x^2 ?

OpenStudy (anonymous):

4x+3?

Directrix (directrix):

3x^2 -11x - 20 = (3x+4) * (x )

Directrix (directrix):

3x times 4x = 12 x^2 -->doesn't work

OpenStudy (anonymous):

is it positve 3?

Directrix (directrix):

3x times 3 = 9x.

OpenStudy (anonymous):

yes

Directrix (directrix):

Oh, you mean ( x + 3) as the second factor?

OpenStudy (anonymous):

yes

Directrix (directrix):

(3x+4) * (x + 3 ) = 3x^2 -11x - 20 ?? 3x^2 + 9x + 4x + 12 Nope.

Directrix (directrix):

We could guess forever.

OpenStudy (anonymous):

xDD i think lol and another one :O

Directrix (directrix):

Here is where we are: 3x^2 -11x - 20 = (3x+4) * (x ) We have to get -20 for the last term. 4 times what equals - 20 ?--->

OpenStudy (anonymous):

i think its x-3?

Directrix (directrix):

4 times - 3 is not -20.

OpenStudy (anonymous):

i mean 2?

OpenStudy (anonymous):

i mean 5 sorry :o

Directrix (directrix):

4 times 5 is close but 4 times 5 does not equal -20

OpenStudy (anonymous):

hmmmm

OpenStudy (anonymous):

i think we need to make one of them a negative right?

Directrix (directrix):

Yes.

OpenStudy (anonymous):

so-5?

Directrix (directrix):

Yes

OpenStudy (anonymous):

its x-5?

Directrix (directrix):

3x^2 -11x - 20 = (3x+4) * (x - 5 )

Directrix (directrix):

That works.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[6x^2+11x-10=(2x+5)(?)\]

Directrix (directrix):

It's your turn to do this one. :) You come up with the factors, and I will check.

OpenStudy (anonymous):

i'll be guessing dou

Directrix (directrix):

That's what I ended up doing because you didn't like factoring by grouping.

OpenStudy (anonymous):

2x+1

OpenStudy (anonymous):

lol actually this s factoring by grouping.. and i need to do factor diamond

OpenStudy (anonymous):

its like two steps first is factoring by grouping and factoring diamond

Directrix (directrix):

That diamond thing is sophisticated guessing for me.

OpenStudy (anonymous):

x. x so can we do factoring by grouping?

Directrix (directrix):

(2x+1)*(2x+5) = 4x^2 + 12x + 5 --> This is from your guess.

Directrix (directrix):

It didn't work.

OpenStudy (anonymous):

2x-5?

Directrix (directrix):

I'm going to group.

OpenStudy (anonymous):

is it 6x10?

OpenStudy (anonymous):

6x10=60 ryt and wet going to make one of them a negative?

Directrix (directrix):

6 + 10 is not 11

Directrix (directrix):

15 and -4.

Directrix (directrix):

x^2 + 11x - 10 = x^2 + 15x - 4x - 10

OpenStudy (anonymous):

5x+2?

Directrix (directrix):

This thread is so long that I have lost the problem.

Directrix (directrix):

(2x + 5) * ( 3x + 2) That is my last factoring problem on this puzzle.

OpenStudy (anonymous):

so its 3x+2?

OpenStudy (anonymous):

3x-2?

Directrix (directrix):

6x^2 + 15x - 4x - 10 = 3x(2x + 5) - 2(2x + 5) = (2x + 5) * ( 3x - 2). Right.

OpenStudy (anonymous):

owoo that was brain storm >,<

Directrix (directrix):

The more of this stuff you do, the better you get. Except, I seem to be getting worse.

OpenStudy (anonymous):

ohh yah sure cuz when im learning this i was lazy thats why i came up here >.<

Directrix (directrix):

What is the next factoring problem?

OpenStudy (anonymous):

how abut this? \[7x^2+13x-2=(x+2)(?)\]

OpenStudy (anonymous):

xDD under the typing box thou v v v v v

OpenStudy (anonymous):

actually this factoring group so on this is the new lesson on our school e. e''''

OpenStudy (anonymous):

and imto lazy about it

OpenStudy (anonymous):

xDD uhh nope o. o

OpenStudy (anonymous):

ohh well i better rap dis up cuz im gonna go early tommorow well thanks fo the help :)

Directrix (directrix):

Okay. See later on here.

OpenStudy (anonymous):

ok byee

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