The probability that a man will hit a target is 2 / 3. If he shoots at the target until he hits it for the first time, find the probability that it will take him 5 shots to hit the target
@Directrix @jim_thompson5910
this one is a hard one
This is basically asking the question of "what is the probability that he will hit the target on the 6th try" This is assuming that once he hits the target, he can no longer shoot it
So you would use the geometric distribution to answer this question
which means you use this formula P(X = k) = (1-p)^(k-1)*p where p = probability of success of each individual and independent trial k = trial number where the first success is encountered
i know the book says its 2 / 243, but i dont know process
you just plug in p = 2/3 and k = 6 evaluate and simplify
got it. thmks
oh wait, k = 5, not 6 but everything else is still the same
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