find the value of c for which the line 3x+cy=5 (c) is parallel to the line 2x+y=-1 (d) has equal x and y-intercepts (e) is perpendicular to the line y-2=3(x+3)
a) replace \(x\) by \(3\) and \(y\) by 1 solve \(3\times 3+c\times 1=5\) for \(c\)
To find the answer to a, plug the x coordinate (3) in to x and the y coordinate (1) in to y. So 3(3)+c(1)=5. Then solve for c. 9+c=5, 9-9+c=5-9, c=-4. For b, plug 0 in for x in the equation. 3(0)+cy=5, cy=5, c=y/5. I know that looks like a weird answer, and I'm not 100% sure it's right, but it's the best I can do with three variables. Parallel lines have the same slope, so the best way to do c is rearrange both of those into slope-intercept form. The first one becomes (cy=5-3x, y=(5-3x)/c) and the second becomes (y=-1-2x). The slope of the first is (-3x/c) and the second is (-2x). To find the c for which this works, set them equal to each other and solve. (-3x/c=-2x, -3x/c*c=-2x*c, -3x=-2xc, -3x/-2x=-2xc/-2x, 3/2=c). Any other helpers that might read through this, one of you guys help him (or her) with d and e. I'm not so great at those.
tnx singlesixx and satellite73
(b) is parallel to the y-axis a line parallel to the y-axis has an undefined slope. if we re-write 3x+cy=5 as y= (-3/c) x + 5/c we can make the number in front of the x (which will be the slope) undefined by dividing by 0. In other words, let c=0 another (maybe better) way is to know that a line parallel to the y-axis has no y in its equation so if we change 3x+c y = 5 to 3x =5 or x= 5/3 we get a line parallel to the y-axis to do this, we have to set c=0 to make the c*y part "go away"
b is correct phi,tnx pls what about c,d & e?
to do (c) is parallel to the line 2x+y=-1 you first have to figure out the slope of 2x+y=-1 to find the slope, you have to "solve for y" can you do that ?
"solve for y" means getting the y by itself on the left side of the = sign.
y=-2x+1 is that?
not very sure
close you start with 2x+y=-1 you want to y by itself. if you add -2x to both sides you get -2x+2x+y= -2x -1 the -2x+2x is 0 and 0 +y is y so the left side is y= -2x -1 you were close what is the slope of y= -2x -1 ?
the reason we write it in the form y= mx + b is because m (the number in front of the x) is the slope.
and what is C?
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