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Mathematics 22 Online
OpenStudy (anonymous):

5^x=4^(x+3)

OpenStudy (mathstudent55):

Start by taking the log of both sides.

OpenStudy (anonymous):

so: log5^x = log4^x+3 ?

OpenStudy (anonymous):

or: xlog5 = x+3log4 ?

OpenStudy (anonymous):

xlog5 = (x+3)log4 now tnotice that log5 and log4 are just some numbers, so: xlog5-xlog4=3log4 x(log5-log4)=3log4 x=3log4/(log5-log4)

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

yaa i got it, thank you very much

OpenStudy (anonymous):

yw

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