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what is the measure of the secant DC ?
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For secants intersecting outside a circle, you have: (CB)*(CA) = (CD)*(CE)
should i multiply CB and CA?
Yes, since you know their lengths.
and CD and CE right ?
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26= CD*14
Be careful, CB = 4, what is CA?
6.5?
BA = 6.5 CA = CB + BA
What is CA?
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10.5
Now you got it. Now do CB * CA
42
CB * CA = CD * CE 4 * 10.5 = CD * 14 42 = CD * 14 Now solve for CD
Yes, 42 is right.
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Cd= 28 ?
42 = CD * 14 CD = 42/14 42/14 is not equal to 28
then its 3
That's much better. That's it. Just remember that when you have two secants that intersect outside a circle, the product of one secant and its exterior segment equals the product of the other secant and its extrior segment. |dw:1363643678081:dw|
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