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Mathematics 16 Online
OpenStudy (anonymous):

what is the measure of the secant DC ?

OpenStudy (anonymous):

OpenStudy (mathstudent55):

For secants intersecting outside a circle, you have: (CB)*(CA) = (CD)*(CE)

OpenStudy (anonymous):

should i multiply CB and CA?

OpenStudy (mathstudent55):

Yes, since you know their lengths.

OpenStudy (anonymous):

and CD and CE right ?

OpenStudy (anonymous):

26= CD*14

OpenStudy (mathstudent55):

Be careful, CB = 4, what is CA?

OpenStudy (anonymous):

6.5?

OpenStudy (mathstudent55):

BA = 6.5 CA = CB + BA

OpenStudy (mathstudent55):

What is CA?

OpenStudy (anonymous):

10.5

OpenStudy (mathstudent55):

Now you got it. Now do CB * CA

OpenStudy (anonymous):

42

OpenStudy (mathstudent55):

CB * CA = CD * CE 4 * 10.5 = CD * 14 42 = CD * 14 Now solve for CD

OpenStudy (mathstudent55):

Yes, 42 is right.

OpenStudy (anonymous):

Cd= 28 ?

OpenStudy (mathstudent55):

42 = CD * 14 CD = 42/14 42/14 is not equal to 28

OpenStudy (anonymous):

then its 3

OpenStudy (mathstudent55):

That's much better. That's it. Just remember that when you have two secants that intersect outside a circle, the product of one secant and its exterior segment equals the product of the other secant and its extrior segment. |dw:1363643678081:dw|

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