Question

(x+2)^2/3 = 9 . HELLLLLP PLEASSE

Answer 1

$$x = \sqrt{27} - 2$$

Answer 2

how did you get that ?

Answer 3

please explain

Answer 4

(x+2)²/3 = 9
(x+2)² = 27
(x+2) = +/-sqrt(27)
$$x = \pm \sqrt{27} - 2$$

Answer 5

thank you

Answer 6

the exponent is 2 over 3 just to let you know

Answer 7

it is $$(x+2)^{2/3}$$ or $$((x+2)^2)/3$$ ?

Answer 8

ohhh ok, sorry

Answer 9

the first one

Answer 10

let do again

Answer 11

okay

Answer 12

(x+2)^(2/3) = 9
(x+2) = 9^(3/2)
x = 27 -2
x = 25

Answer 13

how did you get 27 from 9^(3/2) ?

Answer 14

Ok, 9^(3/2) = $$\sqrt{9^3}$$ = $$\sqrt{729}$$ = 27

Answer 15

Oh okay (: thank you . do you mind helping me with another ?

Answer 16

sure

Answer 17

(3x+9)^(3/4) = 81

Answer 18

is it 27 ?

Answer 19

or 6 i mean

Answer 20

(3x+9)^(3/4) = 81
(3x+9) = 81^(4/3)
x = (1/3) * (-9 + 243*3^(1/3))
x = -3+81*3^(1/3)

Answer 21

wait so what is the answer?

Answer 22

x = -3+81*3^(1/3)

Answer 23

i dont get it

Answer 24

$$x = -3 + 81\sqrt[3]{3}$$

Answer 25

i dont understand how you got that

Answer 26

ok, let's start again from here:
(3x+9) = 81^(4/3)
$$3x+9 = 243\sqrt[3]{3}$$
$$3x = -9 + 243\sqrt[3]{3}$$
$$x = -3 + 81\sqrt[3]{3}$$

Answer 27

ohhhhhhhhhhhhhhhhhhhhhh

Answer 28

thanks

Answer 29

wait how did you get 243?

Answer 30

81^(4/3) = $$(\sqrt[3]{81})^4 = (3\sqrt[3]{3})^4 = 243\sqrt[3]{3}$$

Answer 31

oh okay i understand now

Answer 32

or you can see in this way:
$$\sqrt[3]{81^4} = 243\sqrt[3]{3}$$

Answer 33

got it?