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Physics 15 Online
OpenStudy (anonymous):

How do you derive the expression e2=p2c2+(mc2)2?

OpenStudy (vincent-lyon.fr):

Use : \(E=\gamma mc^2\) \(p=\gamma mv\) \(\gamma =(1-v^2/c^2)^{1/2}\) Write \(p^2c^2 +m^2c^4\) , factorise \(\gamma ^2m^2c^4\), and simplify.

OpenStudy (anonymous):

@Vincent-Lyon.Fr I thought that's called verify. Without using some deep maths, I guess using those equations and try to eliminate v is the simplest way to derive the relation.

OpenStudy (vincent-lyon.fr):

Yes, but you must eliminate both v AND \(\gamma\), which makes the derivation a bit more complicated. That's why I preferred verification. As a mathematical proof, they have the same validity.

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