Mathematics
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OpenStudy (anonymous):
Differentiate. Answer with all positive exponents. 1) h(r)= (r^2+4r-6)/(9r+8)
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OpenStudy (anonymous):
Do you know quotient rule?
OpenStudy (anonymous):
Isnt that rewriting the equation like this (r^2+4r-6)x(9r+8)+(r^2+4r-6)x(9r+8)?
OpenStudy (anonymous):
But taking the derivative once on each side right?
OpenStudy (anonymous):
\[\frac{d}{dx}\frac{f(x)}{g(x)}=\frac{f'(x)g(x)-f(x)g'(x)}{g(x)^2}\]
OpenStudy (anonymous):
Ohh wow thanks. That's helpful to finally see something like that.
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OpenStudy (anonymous):
(r^2+4r-6)'x(9r+8)-(r^2+4r-6)x(9r+8)' /(9r+8)^2 is that right?
OpenStudy (anonymous):
Then you just need to do the differentiation and simplify (optional).
OpenStudy (anonymous):
Could I work it out and have you try it?
OpenStudy (anonymous):
k
OpenStudy (anonymous):
9r^2+16r+86/72r^2+126r+64?
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OpenStudy (anonymous):
\[\huge\frac{ (2r+4)(9r+8)-9(r^2+4r-6) }{ (9r+8)^2 }\]
OpenStudy (anonymous):
The numerator is correct, but there is some calculation mistakes in the denominator.
OpenStudy (anonymous):
Thanks deena123
OpenStudy (anonymous):
\[(9r^2+8)=81r^2+144r+64\]
OpenStudy (anonymous):
but the denominator doesn't need to be multiplied right agostino?
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OpenStudy (anonymous):
Typo lol
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
\[(9r+8)\]
OpenStudy (anonymous):
could i leave it as (9r+8)^2?
OpenStudy (anonymous):
welcome :)
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Yeah, you can.
OpenStudy (anonymous):
Sometimes it is better to leave it there as you may cross it out with the numerator.
OpenStudy (anonymous):
Alright, thanks for the help you guys, I'm new to this site so is there a way I can honor you guys?
OpenStudy (anonymous):
Participate more and be active. :P