Question

find the percent of each school day (based upon 24-hour day) budgeted for the following activities. Find to the nearest whole percent. Sh…

Answer 1

This is similar to the last problem. It is a "without replacement" problem because once a drink is withdrawn, it is gone and cannot be selected again.

P = P(M) x P(W | given that there is now one less drink available)

P(M) = # of milks over the number of drinks

P(W | given that there is now one less drink available) = # of waters over one less than the total number of drinks, because a milk has been withdrawn by this time.

Answer 2

Could u write the fraction for me?

Answer 3

That is the point where you can do well to write the fractions, but I will help you out a bit.

How many total drinks are there? Just add them up. That will be the denominator for the first fraction, the P(M). The numerator is the # of milks.

Answer 4

For the second fraction, the numerator is the # of waters, and the denominator is one less than the total number of drinks that you are starting with. That gives both fractions. Now, just multiply them and simplify.

Answer 5

That's all the information anyone can give you without just giving you the answer. You did the last problem and got it, so you should be able to do this one because it's the same.

Answer 6

c?

Answer 7

Yes, you got it! Good job!

Answer 8

:)