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Graph the following log equation: y+ log(base1/3)(x-2) Increase or Decreasing? X Intercept? Vertical Asymptote? Domain Range
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\[y = \log_{1/3}(x-2) \]
Domain: x - 2 > 0 => x > 2
Range: R
Log is increasing function
it has vertical asymptote of x = 0
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What about the x-intercept? @Kanwar245
x = 3
Can you show me how you got that? Thank you so much! @Kanwar245
x-intercept means where it crosses x-axis, i.e x - 2 = 1 => x = 3 since log 1 = 0
log (x-2) = 0 when x - 2 = 1
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Thank you so much! @Kanwar245
How would I sketch the graph? @kanwar245
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