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Mathematics 16 Online
OpenStudy (anonymous):

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 +19.6t + 58.8. What is the object's maximum height? A. 58.8 B. 194.04 C. 78.4 D. 117.6

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

I think the answer is A.

OpenStudy (anonymous):

@Mertsj

jimthompson5910 (jim_thompson5910):

it's not A, you need to find the vertex, not the y-intercept

jimthompson5910 (jim_thompson5910):

the y coordinate of the vertex

OpenStudy (mertsj):

Find the vertex of that parabola.

OpenStudy (mertsj):

It couldn't be A because it was launched from a height of 58.8 so it would have to go higher than that.

OpenStudy (anonymous):

okay now Im getting C?

OpenStudy (mertsj):

That's what I got.

jimthompson5910 (jim_thompson5910):

better, it's C

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