Question

The measure of side AB =

Answer 1

Have you tried the Pythagorean Theorem since it is a right triangle?

Answer 2

no

Answer 3

That would be a good thing to use.

Answer 4

i need help with that

Answer 5

Are you trying to find a leg or the hypotenuse?

Answer 6

leg

Answer 7

So:
\[(AB)^2+(\frac{t}{2})^2=t^2\]

Answer 8

Solve that for AB

Answer 9

4

Answer 10

\[(AB)^2+\frac{t^2}{4}=t^2\]
\[(AB)^2=\frac{3t^2}{4}\]
\[\sqrt{(AB)^2}=\sqrt{\frac{3t^2}{4}}\]
\[AB=\frac{t}{2}\sqrt{3}\]