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Mathematics 8 Online
OpenStudy (anonymous):

Checking Answers Which kind of function best models the set of data points (–3, 18), (–2, 6), (–1, 2), (0, 11), and (1, 27)? I got none of the above

OpenStudy (anonymous):

linear quadratic exponential none of the above

OpenStudy (ash2326):

Find the difference between x and y for two pairs -2-(-3) , 6-18 1, -12 Now you do the same thing for (-2, 6) and (-1, 2)

OpenStudy (anonymous):

So quadratic?

OpenStudy (ash2326):

No we can't say anything right now. find the difference :)

OpenStudy (anonymous):

-8,-3?

OpenStudy (anonymous):

It's linear

OpenStudy (anonymous):

thanks for giving me a boost :)

OpenStudy (ash2326):

no, not linear

OpenStudy (anonymous):

oh really

OpenStudy (ash2326):

(-1-(-2), (2-6) 1, -4

OpenStudy (ash2326):

for same change in x 1 , there are different changes in y so it's not linear :)

OpenStudy (anonymous):

yeah so its exponential?

OpenStudy (anonymous):

if its not linear or exponential ... then quadratic

OpenStudy (ash2326):

As x increase, y decreases but as x increases beyond 0 y increases. An exponential will either decrease or increase. So it's not exponential

OpenStudy (anonymous):

Its quadratic

OpenStudy (ash2326):

let's confirm that, it could be none also

OpenStudy (anonymous):

okay...but Im pretty sure its quadratic..granted its just a kind of educated guess it seems to fit

OpenStudy (ash2326):

(–3, 18), (–2, 6), (–1, 2), (0, 11), and (1, 27) let's find the first differences (1, -12) (1, -4) , (1, 9) (1, 16) Now differences of these (0, 8) (0, 13) (0, 7) Difference in y is not same so it's not quadratic :)

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