Question

A bag contains 3 red marbles, 4 blue marbles, and 5 white marbles. What is the probability of pulling out a white marble, and then a blue marble if none are replaced?

Answer 1

P (WB) = 5/12 * (4/11)

Answer 2

What is the probability of pulling out a white marble??

Answer 3

@chuck83 answer me!

Answer 4

i'm the one asking for help!

Answer 5

i asked a part of it

Answer 6

okay do u know how to calculate the probability ?@chuck83

Answer 7

nope

Answer 8

Probability = (number of events favourable)/(number of total events)

for example in a die, probability of getting even number if, we want to find
then Counting the favourable events
what are the favourable events = getting 2,4,6 so there are 3 favourable outcomes
total events are 1,2,3,4,5,6 , so there are 6 events on total

So the probability of getting even number is 3/6
that gives us 0.5
[ remember that probability never exceeds 1 as in the extreme cases
Favourable events can be zero as in " getting 7 on the 6 sided dice"
or favourable events can be total events as in " getting any number on 6 sided dice"]

Answer 9

Thats for how to calculate Probability basically.

Answer 10

In your problem given "A bag contains 3 red marbles, 4 blue marbles, and 5 white marbles. What is the probability of pulling out a white marble, and then a blue marble if none are replaced?"
If none are replaced the number of marbles available for first picking would be 3R+4B+5W = 3+4+5 = 12 marbles
in the first picking one marble is taken out so the availble marbles are 12-1 = 11
now probability of picking white marble:
favourable events are 5 as there are 5 marbles of white color
and total marblesare 12
so the probability of pulling out a white marble = 5/12
now probability of pulling out a blue marble:
favourable events are 4 as there are 4 marbles of blue color
total marbles now become 12-1 = 11
so probability of pulling out a blue marble = 4/11
so probability on the whole is (5/12)*(4/11) = 20/132

Answer 11

@chuck83 got it?