Question

What are some solutions of the equation.

Answer 1

\[\tan^2x+\tan x-2=0\]

Answer 2

let y = tan x
you have
y^2 + y - 2 = 0
(y-2)(y+1) = 0

Answer 3

to tan x = 2 or tan x = -1

Answer 4

sorry it should be
(y+2)(y-1) = 0

Answer 5

so tan x = -2 or tan x = 1

Answer 6

let \(\tan x=y\)
you get
\[y^2+y-2=0\\
(y+2)(y-1)=0\\
y+2=0\qquad,\qquad y-1=0
\]
find y,
but y=tan x
so, find "x"

Answer 7

lol thats what I did

Answer 8

@Kanwar245 lol. yes..

Answer 9

\[0<x<2\pi\]

Answer 10

@electrokid and @Kanwar245