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How can the polynomial 6d^4 + 9d^3 – 12d^2 be factored?
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Someone please help me!
it would be 24
factor out \(3d^2\) first
9
9? where?
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3d^2= 9?
\[3d^2(2d^2+3d-4)\] now factor the quadratic..
I don't know what a quadratic is..
ok, so you have\[ 6d^4+9d^3-12d^2\\ \qquad=3d^2(2d^2+3d-4) \] now, find two number whose product is (2)(-4)=-8 and whose sum is +3
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