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How would i plug in for this 3x-7=5x+19 3x-5x=19+7 -2x=26 x=26/-2 x=-13
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wait nvm i think i got it! i just have the problem wrong ):
To proof that your solution is correct, follow the following template: Sub x = -13 into 3x-7=5x+19, LHS = 3(-13) - 7 = Some Answer (not gonna do your work for you ;P) RHS = 5(-13)+19 = Some Answer = (or) \(\neq\) LHS Therefore, x = -13 is (not) a solution to the equation 3x-7=5x+19.
*prove. Not gonna retype :P
i know thank you! thats why i was confused because i worked it out wrong!
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