Joe has 4 red pens, 1 green pen, 2 blue pens, and 3 black pens.
What is the probability he will randomly select a black pen and then,without replacing it, randomly selecti a blue pen?

Question

anonymous · Answer

@AriPotta

aripotta · Answer

OH I'M SORRY. I'M NOT GOOD WITH PROBABILITY

anonymous · Answer

ITS OK ARI

raden · Answer

P(Black) = 3/10
P(Blue) = 2/9
multiply of both

anonymous · Answer

event A: selecting "1" black from a total of (4+1+2+3)=10;
$$P(A)={3\over10}$$
event B: selecting "1" blue from the remainning "9"
$$P(B)={2\over9}$$
now, the events are mutually independent...
$$P(A\cap B)=P(A)\times P(B)={3\over10}\times{2\over9}$$

anonymous · Answer

Oh, ok, thanks!

anonymous · Answer

IDK who to give BEST ANSWER to. LOL.

anonymous · Answer

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