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14x^6- 8x^4 Divided by 2x^3 (the first part of the numbers are at the top and the second at the bottom of a fraction)
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Think of it like this: \[\frac{14x^6}{2x^3}-\frac{8x^4}{2x^3}\]
but the exponenets are different so I still don't know how to solve :/
Use this property: \[\frac{a^m}{a^n}=a ^{m-n}\]
making the answer 7x^3-4x^-1 ?
\[7x^3 -4x^1\]
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