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Mathematics 11 Online
OpenStudy (selena2345):

The capacity of the gas tank in Jennifer"s car is x gallons. She can drive 28 miles for each gallon of gas in the tank. Jennifer filled the tank completely and drove 98 miles. She then stopped and added 2 more gallons of gas. Part A: How many gallons of gas did Jennifer use to drive 98 miles ? Part B: Write an equation to find how far Jennifer could drive with the gas in her gas tank. Part C: Use the equation from Part B to find how far Jennifer could drive if her gas tank has a capacity of 18.5 gallons.

OpenStudy (selena2345):

Aripotta

OpenStudy (aripotta):

well for a, divide 98 by 28

OpenStudy (selena2345):

98/28=3.5

OpenStudy (aripotta):

so a is 3.5 gallons

OpenStudy (selena2345):

what about part b and part c

OpenStudy (aripotta):

y = 28(x - 1.5)

OpenStudy (aripotta):

do you know how i got that?

OpenStudy (selena2345):

no

OpenStudy (selena2345):

what about part c

OpenStudy (aripotta):

so x is the tank's capacity. and we know she only used 3.5 gallons. so x - 3.5. but then she added 2 gallons. so x - 3.5 + 2 which simplified is x - 1.5. and she can get 28 miles per gallon, so we multiply that by 28

OpenStudy (aripotta):

with part c you just substitute x with 18.5

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