**PLEASE HELP** An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object’s position from the top of the tower at 1.0 s intervals. Make a position-time graph for the object’s motion. In your response, show what you are given, the equation that you used, any algebra required, a table of data, and your graph. g = 9.8 m/s2
Using the equation .. d = ut + ½.at² .. Given .. initial velocity, u = 0 (falling from rest) acceleration, a = +9.80 m/s² .. (taking down as the convenient positive direction) Time = 1.0s, 2.0s, 3.0s, 4.0s, 5.0s Using .. d = ½.at² each time .. (each calculation is the distance from the top) For 1.0s .. d = ½ x 9.80 x (1²) = 4.90 m For 2.0s .. d = ½ x 9.80 x (2²) = 19.60 m 3.0s .. d = 44.10m .. (you show the working for the rest) 4.0s .. d = 78.40 m 5.0s .. d = 122.50m Plot distance (displacement from the top) on y-axis against time on the x-axis (label axes and give units for each).The line of best fit will be a smoothly upward curving line getting progressively steeper.. don't join graph points with straight lines !
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