Question

Simplify quantity 12 x minus 96 over quantity x squared minus 4x minus 32 all over quantity 6 x squared minus 6 x minus 12 over 3 x plus 3 ?

Answer 1

\[\frac{ \frac{ 12x-96 }{ x^2-4x-32 } }{ \frac{ 6x^2-6x-12 }{ 3x+3 } }\]

Answer 2

\[\frac{ 12x-96 }{ x^2-4x-32 }*\frac{ 3x+3 }{ 6x^2-6x-13 }\]

Answer 3

can you solve it now

Answer 4

so, it's \[\frac{ 36x^2-288 }{ 6x^4+24x^2+416 }\] right?

Answer 5

no
dont solve it like that

Answer 6

factorize the terms

Answer 7

So then it's \[\frac{ 18x^2-144 }{ 3x^4+12x^2+208 }\]

Answer 8

oh god
do you know factorization?

Answer 9

Yes, you find the gcf and remove it from the terms, right?

Answer 10

-_-"

Answer 11

12x-96
how else can you write this?

Answer 12

12(x-8)

Answer 13

good

Answer 14

and 3x+3?

Answer 15

3(x+1)

Answer 16

now
\[x^2-4x-32\]
can you factorize this?

Answer 17

(x-8)(x+4)

Answer 18

very good
and the last term
\[6x^2-6x-13\]

Answer 19

6(x+1)(x-2)

Answer 20

it was 12 not 13
sorry
and good
now put these values in the equation i gave you
and solve it
what you get?

Answer 21

\[\frac{ 12(x-8) }{ (x-8)(x+4) }\times \frac{ 3(x+1) }{ 6(x+1)(x-2) }\]

Answer 22

now cancel the terms
x+1 ,x-8 gets canceled
and 2 times 6 is 12 so 6 gets canceled and 12 becomes 2
tell me the final answer

Answer 23

\[\frac{ 6 }{ x^2+2x-8 }\]

Answer 24

dont solve the brackets
\[\frac{ 6 }{ (x+4)(x-2) }\]
is your answer

Answer 25

Oh, okay, Thanks!

Answer 26

you are welcome

Answer 27

and p.s.
\[\frac{ \frac{ a }{ b } }{ \frac{ c }{ d } } = \frac{ a }{ b }*\frac{ d }{ c }\]

Answer 28

Okay, Thanks!

Answer 29

:)