Solve the following system of equations.

3x + 3y + 2z = -5
x + y + 3z = -4
2x + 2y + 5z = -7

Question

Solve the following system of equations.

3x + 3y + 2z = -5
x + y + 3z = -4
2x + 2y + 5z = -7

anonymous · Answer

do your own work feather

anonymous · Answer

Helpppppppppppppp

unklerhaukus · Answer

3x + 3y + 2z = -5      i
x + y + 3z = -4          ii
2x + 2y + 5z = -7      iii


ii+iii

3x + 3y + 8z = -11

anonymous · Answer

How what? im really bad at math

unklerhaukus · Answer

ill show you what i did 

ive added the left hand sides together
 and also the right hands sides together 

ii+iii
(x + y + 3z)+[2x + 2y + 5z]= (-4) +[-7]

x +2x  + y+2y+  3z+5z= -4 +-7

3x + 3y + 8z = -11

anonymous · Answer

A. (-4, -3, 1)	
	 B. (-4, 3, -1)	
	 C. (4, -3, -1)	
	 D. (-4, -3, -1)

anonymous · Answer

i have too get an answer like that

unklerhaukus · Answer

does what i have done so far make sense to you?

anonymous · Answer

yes ! (:

unklerhaukus · Answer

lets call our result     iv,       {just to give it a name}

3x + 3y + 8z = -11   iv

unklerhaukus · Answer

now what do you get when you takeaway i from iv

iv - i
(3x + 3y + 8z)-[3x + 3y + 2z] = (-11)-[-5]

can you simplify this @alexislovier?

anonymous · Answer

i have no idea !

unklerhaukus · Answer

its a very similar to the first step

anonymous · Answer

okayy

unklerhaukus · Answer

try it