Question

I need help please. (:

Answer 1

\[10\sqrt[4]{96}=10\sqrt[4]{3(32)}=10\sqrt[4]{3(2^5)}=20\sqrt[4]{6}\]

Answer 2

Thanks @myko !(: You're a life saver! Can you help me with this one?

Answer 3

\[\sqrt{x+2}=x+2\]\[\sqrt{x+2}=x+2\]Squaring both sides:-
\[x+2=x^{2}+4x+4\]Taking all terms to one side and factorising:-\[=>x ^{2}+3x+2=0\]\[=>x ^{2}+x+2x+2=0\]\[=>x(x+1)+2(x+1)=0\]\[=>(x+1)(x+2)=0\]Hence,\[x=-1\]or\[x=-2\]

Answer 4

1st line written twice(would have been just once)..:)

Answer 5

Lets verify that
Putting x=-1
\[\sqrt{-1+2}-2=-1\]
Putting x=-2
\[\sqrt{-2+2}-2=-2\]
Both the values satisfy RHS of the original equation respectively,
Hence verified