Question

How would I solve x(x-3) - 3x(x-4) = -4 * x(x-4) for x?

Answer 1

so multiply through.

Answer 2

x(x-3) = x^2-3x

Answer 3

-3x*x = -3x^2

-3x*-4 = +12x

try to do the same for the right side.

Answer 4

and addd 4 to both sides?

Answer 5

why?

Answer 6

My mistake.. its being multiblied by -3x. so i should have 12x=12x and x=1?

Answer 7

on the left side you have

x^2-3x-3x^2+12x

on the right side you have

-4x(x-4)

which is

-4x^2+16x

so you have

x^2-3x-3x^2+12x = -4x^2+16x

simplify the left side of the equation

-2x^2+9x = -4x^2+16x

add 4x^2 to both sides

2x^2 +9x = 16x

subtract 9x from both sides

2x^2 = 7x

divide both sides by x

2x = 7

x = 7/2

or 0.

Answer 8

Thank you for breaking it down step by step! greatly appreciated

Answer 9

you're welcome