Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

The graph of y = ax2 + bx + c is shown below. Determine the solution set of 0 = ax2 + bx + c.

OpenStudy (anonymous):

quadratic formula :D (-b+_ squareroot of (b^2 - (4)(a)(c)))/(2a)

OpenStudy (anonymous):

+- is plus or minus, it's both

OpenStudy (cwrw238):

if you are required to derive this formula you can use the method of completing the square

jimthompson5910 (jim_thompson5910):

The solutions of 0 = ax^2 + bx + c are the x-intercepts of y = ax^2 + bx + c

jimthompson5910 (jim_thompson5910):

So if for example the graph crosses the x axis at the points (4,0) and (8,0), then the two solutions would be x = 4 or x = 8

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!