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The graph of y = ax2 + bx + c is shown below. Determine the solution set of 0 = ax2 + bx + c.
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quadratic formula :D (-b+_ squareroot of (b^2 - (4)(a)(c)))/(2a)
+- is plus or minus, it's both
if you are required to derive this formula you can use the method of completing the square
The solutions of 0 = ax^2 + bx + c are the x-intercepts of y = ax^2 + bx + c
So if for example the graph crosses the x axis at the points (4,0) and (8,0), then the two solutions would be x = 4 or x = 8
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