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Consider the functions f(x) = 3x2 + 1 and g(x) = x + 3. What is the value of f[g(−1)]? 7 37 13 12
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find g(-1) so -1+3 aka -2, then use that value in F(x) so then F(-2) which is i assume 3(-2)^2+1. so 3(4)+1 or 13.
you could also form a function FoG by taking what g(x)= and plug that right side into the x value of the f(x) function
FoG= (3)(x+3)^2 +1
3x + 9^2 + 1 3x + 81 + 1 3x + 82? I'm confused
you have to take (x+3)^2 first, order of operations, therefore you get x^2+6x+9. that substitutes back in so (3)(x^2+6x+9) +1 simplify it's 3x^2+18x+28. plug in x=-1 you get 3-18+28.. aka 13
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oh ok now i understand
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