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Mathematics 7 Online
OpenStudy (anonymous):

what is the distance between point A and B ?

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

start with figuring out the coordinates of A and B

OpenStudy (anonymous):

point A is (2,2,3) I believe

OpenStudy (anonymous):

point B is (3,2,8) im not sure

ganeshie8 (ganeshie8):

ha you have it almost correct... lets do it step by step

ganeshie8 (ganeshie8):

from origin, A is 2 units along x, 3 units along y, 2 units along z so coordinates of A is (2, 3, 2)

ganeshie8 (ganeshie8):

from origin, B is 5 units along x, 7 units along y, 2 units along z so coordinates of B is (5, 7, 2)

ganeshie8 (ganeshie8):

is that right, ? can u check in the fig and confirm... .

OpenStudy (anonymous):

yes that seems right

ganeshie8 (ganeshie8):

great ! now we just use the distance between two points formula ?

OpenStudy (anonymous):

which is ?

ganeshie8 (ganeshie8):

distance between points \(A(x1, y1, z1)\) and \(B(x2, y2, z2)\) = \(\sqrt{(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2}\)

OpenStudy (anonymous):

I don't understand how im supposed to plug in the numbers

ganeshie8 (ganeshie8):

ok i can teach u that

ganeshie8 (ganeshie8):

A : (2, 3, 2) B : (5, 7, 2)

ganeshie8 (ganeshie8):

these are our coordinates, right ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

A : (2, 3, 2) --> (x1, y1, z1) B : (5, 7, 2) --> (x2, y2, z2)

ganeshie8 (ganeshie8):

plugin the corresponding numbers in formula : \(\sqrt{(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2}\) \(\sqrt{(5-2)^2 + (7-3)^2 + (2-2)^2}\)

OpenStudy (anonymous):

yes! that's what I have. 3^2 + 4^2 + _________ im not sure about the last one

ganeshie8 (ganeshie8):

\(\sqrt{(3)^2 + (4)^2 + (0)^2}\) \(\sqrt{9 + 16}\)

OpenStudy (anonymous):

it would be 25

OpenStudy (anonymous):

would it be a simple 5 or 5 square rooted ?

ganeshie8 (ganeshie8):

u forgot about the squareroot !

ganeshie8 (ganeshie8):

\(\sqrt{9 + 16}\) \(\sqrt{25}\) 5

OpenStudy (anonymous):

okay got it thanks ! let me try the next one

ganeshie8 (ganeshie8):

great ! good luck !

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