Question

How would I go about factoring
128x^3 - 98x ?

thanks so much! :)

I medal people ;)

Answer 1

Pull out what's in common! :)

Answer 2

Step by step instructions, thx :)

Answer 3

nothing's in common

Answer 4

try ;P

Answer 5

omg
they'res NO common factor

Answer 6

x is a common factor, there's a start...

Answer 7

yeah
I already removed x
THEN what ?

Answer 8

I devided by x

Answer 9

I heard in this type of polynomial prob you have to root both
but thats impossible for the second one

Answer 10

I got 2x(8x-7)(8x+7)

Answer 11

so ?

Answer 12

oh, so the answer is (8x-7)(8x+7)?

Answer 13

The answer is 2x(8x-7)(8x+7)

Answer 14

they seem to want it in the format of (8x - 7)(8x + 7)

Thanks for explainig :3

Answer 15

Something's off. To clarify, sfb is right. 2x MUST to be included, unless the original problem was to factor an equation with the polynomial set to 0 (?).

Answer 16

ya
well IDK
they want it in that format!

Answer 17

they say kinda I think in the instructions to root, but that deosn't work ??
please help
thx

Answer 18

Do they want you to find the zeros of that problem?

Answer 19

0s ?
nah
they say
FACTOR COMPLETELY

Answer 20

they want it in (1x-1)(1x+1) kinda format see ?

Answer 21

then sfb's answer is what you're looking for, but you need to include the factor of 2x

Answer 22

they dont want it in that format!

Answer 23

Can you write the original problem down completely? If it just says, factor this polynomial completely ... , then sfb's answer is completely correct and there's no way around it. Maybe there's something that is being asked for that we're overlooking though.

Answer 24

thats all it says
they want it in (1x-1)(1x+1) kinda format see ?

Answer 25

then I'd say that sfb's answer maintains that format, with a factor of 2x thrown in there.

Answer 26

thx! :D