Question

Find the geometric mean of the pair of numbers.

3 and 6

Answer 1

same as last one'
multiply them , take the square root

Answer 2

\(c^2=a\times b\)
c is the geometrical mean of a and b

Answer 3

only this time you do not get a prefect square like the last one

Answer 4

use that or this\[{a\over c}={c\over b}\]

Answer 5

yeah I did and it came out as 18 then when I got 4.24 but I cant figure out what way to write that out

Answer 6

\[\sqrt{9\times 3}=\sqrt{9}\times \sqrt{3}=3\sqrt{3}\]

Answer 7

^^

Answer 8

or use a calculator if you want a decimal approximation

Answer 9

i did use a calculator I am saying I dont know what way to write it out let me show you the options @satellite73