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f(z)= sinz/z^4 the laurent series is 1/z^3 -1/3!z+z/5! my book says the Res(f,0)=the coefficient of z^-1=-1/6. How was the Res(f,0) calculated? In other words...how does one find z^-1 and hence its coefficient?
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-1/3!z^3/z^4 = -1/6 (z^(-1)) <-- this is your residue
the left hand side of your expression isnt making sense to me
what is the coefficient of 1/z ??
-1/3!
ahh i see
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hence -1/6 is the residue
yes
thanks
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