Question

Factor completely: 4x3 + 28x2 + 7x + 49

Answer 1

@sfb

Answer 2

What do you think about this one?

Answer 3

i have no clue at all.... :/

Answer 4

OpenStudy values the Learning process - not the ‘Give you an answer’ process
Don’t post only answers - guide the asker to a solution.

Answer 5

Can you factor the first two terms and last two terms separately?

Answer 6

In other words, can you factor \(4x^3 + 28x^2\)?

Answer 7

And then \(7x + 49\)?

Answer 8

Try \((4x^3-28x^2)+(7x+49)\)

Answer 9

But the question is a little bit different.

Answer 10

yes it would be 4x^2 (x + 7)

Answer 11

and 7(x + 7)

Answer 12

Yep, so you have \(4x^2(x + 7) + 7(x + 7)\)

Answer 13

The rest that follows is simple.

Answer 14

umm.... what do i do ?

Answer 15

wait!! I THINK I HAVE THE ANSWER! ITS (x + 7)(4x^2 + 7)

Answer 16

Hmm... what if you let \(x + 7 = y\)? You then have \(4x^2 y + 7y\). You can factor that...

Answer 17

Yeah!

Answer 18

YAAAAAY MEEEE

Answer 19

thank you lol