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Mathematics 20 Online
OpenStudy (anonymous):

mean value thorem question i got 2 right and 2 wrong

OpenStudy (anonymous):

OpenStudy (zehanz):

If you draw a graph, you get a better idea of how thing look. If you try to solve f'(x)=0, you get x=1. Although there is a local maximum in x=1, it is not the absolute maximum on the give interval. That occurs when x=-1. Also, the absolute minimum cannot be found by differentiation: f is not differentiable in x=0, but f(0)=0 is the absolute minimum.

OpenStudy (sirm3d):

what is f(0) or f(4) (they are equal anyway)? f(x)=x^2-4x+9 f'(x)=2x-4 f'(x)=0: 2x-4=0 x=2

OpenStudy (zehanz):

@sirm3d: the function has changed since my post...Dodo1 has replaced it.

OpenStudy (anonymous):

sorry I posted the wrong question first.

OpenStudy (anonymous):

How about f(0)=f(4)=

OpenStudy (sirm3d):

you can do that. f(0) means the value when x is replaced by 0

OpenStudy (anonymous):

it also says 4. what does this mean

OpenStudy (anonymous):

I got it! thank you for yout help

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