The sum of three times a number and a second number will total 12 or greater. The sum of three times the first number and twice the second number is less than or equal to 15. Find the two numbers. A. first number = 2 and second number = -1 B. first number = 3 and second number = 2 C. first number = 5 and second number = 1 D. first number = 4 and second number = 1
let x be the first number and y be the second number. so 3x+y≥12 and \[3x+2y \le15 \] now it is just a case of solving the equations simultaneously
i really dont know D: @hexagon001
do you get what has been done so far?
am i supposed to divide 3 on both sides @hexagon001
subtract the second eqaution from the first... what do you get?
i think its b.. @hexagon001
yup you are right. i just made a small error in my first equation..its supposed to read 3y.. but nonetheless you are correct
thanks :) @hexagon001
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