Question

Write the equation of the line that is perpendicular to the line y =3 over 2x+4 and passes through the point (-6,3)

A. y=3 over 2x-1
B. y=3 over 2x+3
C. y=-2 over 3x-1
D. y=-2 over 3x+3

Answer 1

@iluvreading

Answer 2

help!!! ):

Answer 3

What do you mean by over 2x+4?

Answer 4

as in a fraction

Answer 5

you mean y=3/2x+4?

Answer 6

yea

Answer 7

I think there is some problem with your question. I know about y=2x+4/3, but i havent done anything like where a xy term comes. I'm afraid i wouldnt be able to help you.

Answer 8

poo

Answer 9

Oh dang. I get it. Your question is this. y=(3/2)x+4 right?

Answer 10

yes

Answer 11

Haha. This is easy then.
slope of the perpendicular line is -2/3 (as m1*m2=-1 in case of perpendicular lines) and it passes through (-6,3).
now write the general equation y=mx+c, you know m,y,x. substitute and find c, and put it back into the equation and you have your line.

Answer 12

huh???

Answer 13

Didnt get it?

Answer 14

no

Answer 15

right now i have a 63

Answer 16

http://answers.yahoo.com/question/index?qid=20100820235355AAuiJpb
This might help you. I think you need to revise your concepts on slopes and straight lines first.
I would have explained, but i'm in a hurry atm.