Question

ive been struggling with the second question.
please help. one gold madal for sure!

Answer 1

what was your derivative?

Answer 2

6x^2-18x-108

Answer 3

thats not it ....

Answer 4

its not? I used this equation for solving the first question

Answer 5

\[3(\frac{2}{3})x^{\frac23-\frac33}-2(1)x^0\]

Answer 6

\[2x^{-1/3}-2=0~:~or~undefined\]

Answer 7

what are the critical points of interest?

Answer 8

I am sorry ! i posted the wrong question

Answer 9

this one!

Answer 10

then 6 18 108 look fine

when does that quadratic match the slope of -3?

when 6x^2 -18x -111 = 0 right?

Answer 11

x^2 -3x = 111/6

x^2 -3x +9/4 = 111/6 + 9/4

(x - 3/2)^2 = 111/6 + 9/4

x = 3/2 +- sqrt(111/6 + 9/4)

Answer 12

so, about -3 and 6 is correct, but they prolly want exact values ... with the sqaure roots

Answer 13

and my 111 is offf, make that 105

Answer 14

Thank you,
I did use quadric form to solve it.
-3 and 6 are correct right?

Answer 15

what do you mean squre root?

Answer 16

the values of the zeros are irrational numbers.

does your program expect you to input them as an approximated decimal? or as an exact representation using the square roots?

Answer 17

I have no idea! I have tried exact num and appricmated number tho :/

Answer 18

i tired 6.055 and -3.055

Answer 19

6x^2 - 18x - 108 = -3

6x^2 - 18x - 105 = 0

3 (2x^2 - 6x - 35) = 0

2x^2 - 6x - 35 = 0

by using the quadratic formula
\[x=\frac{6\pm\sqrt{36-4(-35)(2)}}{2*2}\]
\[x=\frac{6\pm\sqrt{316}}{4}\]
\[x=\frac{6\pm2\sqrt{79}}{4}\]
\[x=\frac{3\pm\sqrt{79}}{2}\]

Answer 20

try:

(3+(79)^(1/2))/2 ,(3-(79)^(1/2))/2 and see if it takes it

Answer 21

or if you have a sqrt button along the side, you might have to use that instead of ^(1/2)

Answer 22

and your approximates are a bit high .... try

-2.9941 , 5.9941

Answer 23

-2.9441, 5.9441 that is

Answer 24

Its not worki g eigther! :/