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dx/dt=k(a-x)
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\[\large \frac{ dx }{ dt } = k(a-x)\] use separation of variables \[\large \frac{ dx }{ a-x } = k dt\] now integrate both sides \[\large \int\limits \frac{ dx }{ a-x } =\int\limits k dt\] \[\large -\ln ( a-x ) = kt + C\]
To finish, multiply it all by -1 first, then take the power of e on both sides. Note that x < a.
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