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Mathematics 13 Online
OpenStudy (anonymous):

find the point on the graph of the function f(x)= f√x that is closest to the point (28,0)

OpenStudy (harsimran_hs4):

f(x) = f * sqrt(x) ?? how come f on the right side

OpenStudy (anonymous):

oh my god im sorry i wrote it wrong its suppose to be

OpenStudy (anonymous):

find the point on the graph of the function f(x)= √x that is closest to the point (28,0)

OpenStudy (harsimran_hs4):

great so let us assume that (x, y) is the required point since it lies on the graph y = sqrt(x) distance of the point (x , y) from (28, 0) is ? can you fill the ?

OpenStudy (anonymous):

im not sure how to do that?

OpenStudy (harsimran_hs4):

distance b/w two points (a,b) and (c, d) is sqrt((a-c)^2 + (b - d)^2) can you now?

OpenStudy (anonymous):

=/

OpenStudy (anonymous):

is it 57/2, √57/2?

OpenStudy (harsimran_hs4):

how could you get a number you should get it in terms of x and y show me the working

OpenStudy (anonymous):

im confused!!!!

OpenStudy (anonymous):

i dont know i cant figure this one out

OpenStudy (harsimran_hs4):

two points (x, y) and (28, 0) instead of (a,b) and (c, d) just plug in the values so what is the distance between them ?

OpenStudy (anonymous):

28?

OpenStudy (harsimran_hs4):

dist is sqrt((28- x)^2 + (y-0)^2) clear ????

OpenStudy (anonymous):

yes...

OpenStudy (harsimran_hs4):

now y = sqrt(x) put this in the dist and tell me what you get

OpenStudy (anonymous):

y=5.29?

OpenStudy (anonymous):

x=28

OpenStudy (anonymous):

i dont know how to figure this out im not getting the right answer..

OpenStudy (anonymous):

the options are

OpenStudy (harsimran_hs4):

now from where did you get y = 5.29 please for God sake this time show me your working even if you are confused

OpenStudy (anonymous):

A. 57/2, √57/2 B. √57/2, 55/2 C. 55/2, √57/2 D. √55/2, 55/2 E.55/2, √55/2

OpenStudy (anonymous):

i plugged it into the equation!!!

OpenStudy (anonymous):

i dont have paint on my comp to send my work

OpenStudy (harsimran_hs4):

use the draw feature given below or just type

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