find the point on the graph of the function f(x)= f√x that is closest to the point (28,0)
f(x) = f * sqrt(x) ?? how come f on the right side
oh my god im sorry i wrote it wrong its suppose to be
find the point on the graph of the function f(x)= √x that is closest to the point (28,0)
great so let us assume that (x, y) is the required point since it lies on the graph y = sqrt(x) distance of the point (x , y) from (28, 0) is ? can you fill the ?
im not sure how to do that?
distance b/w two points (a,b) and (c, d) is sqrt((a-c)^2 + (b - d)^2) can you now?
=/
is it 57/2, √57/2?
how could you get a number you should get it in terms of x and y show me the working
im confused!!!!
i dont know i cant figure this one out
two points (x, y) and (28, 0) instead of (a,b) and (c, d) just plug in the values so what is the distance between them ?
28?
dist is sqrt((28- x)^2 + (y-0)^2) clear ????
yes...
now y = sqrt(x) put this in the dist and tell me what you get
y=5.29?
x=28
i dont know how to figure this out im not getting the right answer..
the options are
now from where did you get y = 5.29 please for God sake this time show me your working even if you are confused
A. 57/2, √57/2 B. √57/2, 55/2 C. 55/2, √57/2 D. √55/2, 55/2 E.55/2, √55/2
i plugged it into the equation!!!
i dont have paint on my comp to send my work
use the draw feature given below or just type
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