Find the maximum value y-value on the graph of y=f(x) f(x)=x^2+6x+3?

I am so confused as to what I put as my answer bc
y= x^2 + 6x + 3
dy/dx = 2x + 6

max value is when dy/dx = 0

2x = -6
x = - 3

y = 9 - 18 + 3
y = -6

coordinates [-6, -6]....However this is a minimum value ...no maximum

Question

Find the maximum value y-value on the graph of y=f(x) f(x)=x^2+6x+3?

I am so confused as to what I put as my answer bc
y= x^2 + 6x + 3
dy/dx = 2x + 6

max value is when dy/dx = 0

2x = -6
x = - 3

y = 9 - 18 + 3 
y = -6

coordinates [-6, -6]....However this is a minimum value ...no maximum

anonymous · Answer

did you try plotting it on a graph and making sure your numbers are correct?

anonymous · Answer

Your work is all correct just check your problem again