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Find all of the zeros of f(x) if f(x) = (x^2 – 4)^3. Identify any multiple zeros. A. {4 (triple zero), –4 (triple zero)} B. {4 (triple zero)} C. {2, –2} D. {2 (triple zero), –2 (triple zero)}
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Please anybody help! :(
Set the function = 0 and solve for x
Did you try that?
Yes, I got (x^8-64)
is it correct until here?
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No, When you cube a binomial, you must multiply the binomial by itself and multiply that answer by the binomial again.
A better approach would be to take the cube root of both sides.
Oh ok, I am sorry
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