Question

True or false?
(sinx+cotx/cosx)^2=tan^2x+2secx+csc^2x

Answer 1

\[(sinx + cotx / cosx)^{2} = \tan ^{2}x + 2secx + \csc ^{2}x\]

Answer 2

@Mertsj

Answer 3

I would start by replacing cot with cos/sin then simplify the complex fraction and square. See where that leads.

Answer 4

I'll do it too. Hopefully we will come to the same conclusion.

Answer 5

when i square it do i square everything.. like numerator and denominator and thanks

Answer 6

yes

Answer 7

so i got: sin^2x + (cos^2x/sin^2x) / cos^2 = tan^2x + 2 (1/cosx) + 1/sin^2