Question

Help! PLEASE! The length of a rectangle is 3ft more than twice its width, and the area of the rectangle is 54ft^2. Find the dimensions of the rectangle

Answer 1

The rectangles perimeter should be w + w + (l + 3) + (l+3).
So, the area should be w * (l+3) = 54 feet squared.
Now calculate the dimensions using this information.

Answer 2

Call the width 'x'.

Width = x Length = x + 3

Area = Length x Width = x(x+3) = x^2 + 3x = 54

Since we know x^2 + 3x = 54, bring 54 over and solve the quadratic to get values of x.

x^2 + 3x - 54 = 0
(x + 9)(x - 6) = 0
x = -9, 6

Since we know that x represents the width of the rectangle, it must be a positive so we scrap the negative solution. Therefore, our solution for the width is x = 6. We know that the length = x + 3 = 6 + 3 = 9.

Has, the dimensions are length = 9 width = 6, 9 by 6.

@maddiemaze