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Algebra 19 Online
OpenStudy (anonymous):

What are the minimum, first quartile, median, third quartile, and maximum of the data set below? 95 85 7.5 85 65 60 100 105 75 85 75

OpenStudy (agent0smith):

First step is to order the data from least to greatest, which I'm sure you can do, then you can easily find everything else.

OpenStudy (anonymous):

Yes, but I'm not confident in finding the first and third quartile. So I'm studying these data sets over and over to instill the process into my brain.

OpenStudy (agent0smith):

Find the first and third quartiles the same way you found the median - once you find the median, split the data into two sets, then basically you're finding the median of each of those.

OpenStudy (agent0smith):

http://web.mnstate.edu/peil/MDEV102/U4/S36/S363.html

OpenStudy (anonymous):

When I got the median, which was 85, I was going to split the data into two sets, but when I do that, am i supposed to have the median (85) as the maximum in the first one, and then as the minimum in the second one?

OpenStudy (anonymous):

As in ....... --> 60 65 75 75 75 (85) and then ....--> (85) 85 85 95 100 105

OpenStudy (anonymous):

Wait, I think I've got it... These are my answers.. Median: 85 Minimum: 60 Maximum: 100 \[Q _{1}\] : 75 \[Q _{3}\] : 95

OpenStudy (agent0smith):

You don't use the median in the data sets, see the link i posted above for an example.

OpenStudy (anonymous):

So it would be 75 for the first set, and 95 for the second set, without the Median. Correct?

Directrix (directrix):

http://easycalculation.com/statistics/box-plot-grapher.php Put your data in query box at the above site, and you can check your work.

OpenStudy (anonymous):

Thank you [:

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