Question

What are the x– and y–intercepts of the graph of y = x2 – 10x + 21?

Answer 1

to get x-intercept take y = 0
in other words x^2 – 10x + 21 = 0
solve for x, by factorization or use the quadratic formula

Answer 2

to get y-intercept take x = 0
y = x^2 – 10x + 21
y = (0)^2 – 10(0) + 21 = ...

Answer 3

dont forget they are represented as coordinat :
for x-intercept : (...,0)
for y-intercept : (0,...)

Answer 4

I don't understand?

Answer 5

x^2 – 10x + 21 = 0
this can be factored
(x - 3)(x - 7) = 0
take each factor be equal zero,
x-3 = 0
so, x=3

also x-7=0
x=7

thus, the x-intercept are (3,0) and (7,0)

Answer 6

to get y-intercept take x = 0
y = x^2 – 10x + 21
y = (0)^2 – 10(0) + 21 = 0 - 0 + 21 = 21
thus, y-intercept at point (0,21)

Answer 7

Thank you

Answer 8

you're welcome