Question

Integration by parts, can't get the final answer

Answer 1

What is the question?

Answer 2

\[\int\limits_{}^{}216x^2\cos(6x)dx\]

Answer 3

so if I make u=cos(6x) du=-6sin(6x)
and dv=216x^2 V=72x^3

Answer 4

You could factor out 216 to make it easier and then integrate by parts so that f = x^2 , f' = 2x, g = sin(6x)/6, and g' = cos(6x)

Answer 5

I'm still doing something wrong and I don't know what

Answer 6

easier use the table integration :)

Answer 7

I don't know what that is

Answer 8

look at this :